tay5876 13/11/2018 M = C (1+i)^(t)30 305,76 = 20 310 (1,029)^(t)30 305,76/ 20 310 = (1,029)^(t)t = log(1,4922)/ log(1,029)t = 14 meses
tay5876
M = C (1+i)^(t)
30 305,76 = 20 310 (1,029)^(t)
30 305,76/ 20 310 = (1,029)^(t)
t = log(1,4922)/ log(1,029)
t = 14 meses