melissamoraes402 01/11/2017 Dados:m = 250 gTi = 16°CTf = 40°Cc = 1,0 cal/g°CQ = ?1cal ≈ 4 joulesQ = m . c . ΔTQ = m . c . (Tf - Ti)Q = 250 . 1 . (40 -16)Q = 250 . 1 . 24Q = 6 000 cal1 cal 4 Joules6 000 cal xx . 1 = 6 000 . 4x = 24 000 Joules de energia
melissamoraes402
Dados:
m = 250 g
Ti = 16°C
Tf = 40°C
c = 1,0 cal/g°C
Q = ?
1cal ≈ 4 joules
Q = m . c . ΔT
Q = m . c . (Tf - Ti)
Q = 250 . 1 . (40 -16)
Q = 250 . 1 . 24
Q = 6 000 cal
1 cal 4 Joules
6 000 cal x
x . 1 = 6 000 . 4
x = 24 000 Joules de energia