carolinegigi 10/05/2018 MOLARIDADE(M)m= n1/v(L)N1=m/MHCI=36,5g/moln1=36,5g 36,5g/mol= 1 molm= 1 mol /2L= 0,5 MOL/ L
carolinegigi
MOLARIDADE(M)
m= n1/v(L)
N1=m/M
HCI=36,5g/mol
n1=36,5g
36,5g/mol= 1 mol
m= 1 mol /2L= 0,5 MOL/ L