ivansouza63 29/05/2017 Q = m.c.∧∅1800 = 300 c (130 - 10)1800 = 300 c 120c = 1800/36000c = 0,05 cal/g°c
ivansouza63
Q = m.c.∧∅
1800 = 300 c (130 - 10)
1800 = 300 c 120
c = 1800/36000
c = 0,05 cal/g°c