fernanda0630 25/02/2018 r=(4,0 + 2,5t²)i + 5,0 tj 5Ti + 5,0J(5X2)I + (5,0)J10I+5J√ 10²+5²√ 100+25 = 11,18m/sTang ¯¹= 5/10=26,56°
fernanda0630
r=(4,0 + 2,5t²)i + 5,0 tj
5Ti + 5,0J
(5X2)I + (5,0)J
10I+5J
√ 10²+5²
√ 100+25 = 11,18m/s
Tang ¯¹= 5/10=26,56°