tokioruiva 03/11/2017 A₁=?a₁₀=1536q=-2 a₁₀=a₁.qⁿ⁻¹ 1536=a₁.(-2)⁹ 1536=a₁.(-512) a₁=1536/-512 a₁= -3(-3,6,-12,24,-48,96,-192,384,-768,1536)
tokioruiva
A₁=?
a₁₀=1536
q=-2 a₁₀=a₁.qⁿ⁻¹
1536=a₁.(-2)⁹
1536=a₁.(-512)
a₁=1536/-512
a₁= -3
(-3,6,-12,24,-48,96,-192,384,-768,1536)