yarawaneska49 15/04/2022 V₁ (volume) = 5 LT₁ (temperatura) = 27°C = 300KV₂ (volume) = ?T₂ (temperatura) = 127°C = 400KV₁/T₁ = V₂/T₂5/300 = V₂/400300V₂ = 2.000V₂ = 2.000/300V₂ = 6,66 L
yarawaneska49
V₁ (volume) = 5 L
T₁ (temperatura) = 27°C = 300K
V₂ (volume) = ?
T₂ (temperatura) = 127°C = 400K
V₁/T₁ = V₂/T₂
5/300 = V₂/400
300V₂ = 2.000
V₂ = 2.000/300
V₂ = 6,66 L