Resposta:

Aplicar D = m / V onde D = de m =

massa V = volume

Dados

D agua = 1g / c * m ^ 3

Volume da a gua=1,5L=1500cm^ 3 =>m=D^ * V

1g/cm^ 3 *1500cm^ 3 ==>m=1500g

Dgelo = 0, 92g / c * m ^ 3

m gelo = magua = 1500g

Vgelo = ?

V = m / D

V = 1500g / 0, 92g / c * m ^ 3

V=1630cm^ 3 ==>1,63L