mariaeduardadeolivei 23/04/2020 A) H3PO4 3 + 1P + 4 ( - 2) = 03 + P - 8 = 0P = 8 - 3P = 5b) H3PO33 + 1P + 3 ( - 2) = 03 + P - 6 = 0P = 6 - 3 P = 3c) HClO41 + Cl + 4 ( - 2) = 01 + Cl - 8 = 0Cl = 8 - 1Cl = 7d) HClO31 + Cl + 3 (-2) = 01 + Cl - 6 = 0Cl = 6 - 1Cl = 5
mariaeduardadeolivei
A) H3PO4
3 + 1P + 4 ( - 2) = 0
3 + P - 8 = 0
P = 8 - 3
P = 5
b) H3PO3
3 + 1P + 3 ( - 2) = 0
3 + P - 6 = 0
P = 6 - 3
P = 3
c) HClO4
1 + Cl + 4 ( - 2) = 0
1 + Cl - 8 = 0
Cl = 8 - 1
Cl = 7
d) HClO3
1 + Cl + 3 (-2) = 0
1 + Cl - 6 = 0
Cl = 6 - 1
Cl = 5