juhbs86544 25/09/2014 PH = - log [H+]epOH = 14 - pHpH = - log(2,5 x 10^-4) = 3,6pOH = 14 - 3,6 = 10,4
juhbs86544
PH = - log [H+]
e
pOH = 14 - pH
pH = - log(2,5 x 10^-4) = 3,6
pOH = 14 - 3,6 = 10,4