tay5876 12/01/2020 2x²-12x+10=0 δ= b²-4ac δ=-12²-4.2.10 δ=144-80 δ=64 x=- b+-√δ 2a x= )+- √64 2.2 x= 12+-8 4 x1= 12+ 8= 20=5 4 4 x2= 12-8= 4=1 4 4 s=( 5,1) *espero ter ajudado*
tay5876
2x²-12x+10=0
δ= b²-4ac
δ=-12²-4.2.10
δ=144-80
δ=64
x=- b+-√δ
2a
x= )+- √64
2.2
x= 12+-8
4
x1= 12+ 8= 20=5
4 4
x2= 12-8= 4=1
4 4
s=( 5,1)
*espero ter ajudado*