nicolle5189 02/06/2015 Massa molar do NaOH = 23+16+1 = 40 g/mol1 mol de NaOH > 40 gx mol de NaOH > 160 gx = 160 / 40x= 4 mols
nicolle5189
Massa molar do NaOH = 23+16+1 = 40 g/mol
1 mol de NaOH > 40 g
x mol de NaOH > 160 g
x = 160 / 40
x= 4 mols