Ristermit 20/01/2022 1)a) mm ( NaOH ) = 23 + 16 + 1 = 40 g/molM = m / mm x VM = 20 / 40 x 2M = 20 / 80M = 0,25 mol/Lb)M = n / VM = 3 / 3M = 1,0 mol/Lc)mm ( HCl) = 1 + 35,5 = 36,5 g/molM = m / mm x VM = 73 / 36,5 x 4M = 73 / 146M = 0,5 mol/Ld) mm ( C₁₂H₂₂O₁₁) = 12 x 12 + 1 x 22 + 16 x 11 = 342 g/mol2000 cm³ / 1000 = 2 LM = m / mm x VM = 684 / 342 x 2M = 684 / 684M = 1,0 mol/Lespero ter ajudado!
Ristermit
1)
a) mm ( NaOH ) = 23 + 16 + 1 = 40 g/mol
M = m / mm x V
M = 20 / 40 x 2
M = 20 / 80
M = 0,25 mol/L
b)
M = n / V
M = 3 / 3
M = 1,0 mol/L
c)
mm ( HCl) = 1 + 35,5 = 36,5 g/mol
M = m / mm x V
M = 73 / 36,5 x 4
M = 73 / 146
M = 0,5 mol/L
d)
mm ( C₁₂H₂₂O₁₁) = 12 x 12 + 1 x 22 + 16 x 11 = 342 g/mol
2000 cm³ / 1000 = 2 L
M = m / mm x V
M = 684 / 342 x 2
M = 684 / 684
M = 1,0 mol/L
espero ter ajudado!