aryanemendes2602 31/03/2018 M(CO₂)=12g+ 2*16g=44gM(H₂O)=2*1g+16g=18g 2C₂H₂+5O₂-->4CO₂+2H₂O4*44,0 g > 2*18,0 g528 g > x gx = 528 * 2 * 18,0 / 4 * 44x = 19008 / 176x = 108 g de H₂O
aryanemendes2602
M(CO₂)=12g+ 2*16g=44g
M(H₂O)=2*1g+16g=18g
2C₂H₂+5O₂-->4CO₂+2H₂O
4*44,0 g > 2*18,0 g
528 g > x g
x = 528 * 2 * 18,0 / 4 * 44
x = 19008 / 176
x = 108 g de H₂O